University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 62: 2.57

Answer

250 km.

Work Step by Step

Call the distance d. The S-waves take a time $t_s=\frac{d}{v_S}$ to travel that distance. The P-waves take a time $t_P=\frac{d}{v_P}$ to travel that same distance. We are told that the time delay is 33s. The faster P-waves arrive first, in less time. $ \frac{d}{v_S}=\frac{d}{v_P}+33s$ $ \frac{d}{3.5km/s}=\frac{d}{6.5km/s}+33s$ $d = 250 km$
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