University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 62: 2.58


The rock will fall 49.8 meters.

Work Step by Step

As an object falls freely, the acceleration is $9.80~m/s^2$. We can write this as $9.80~\frac{(m/s)}{s}$. That is, each second, the velocity increases by 9.8 m/s. As the rock fell, the average velocity was $\frac{40.0~m}{1.00~s}$ which is 40.0 m/s. During the next 1.00-second time interval, the average velocity will increase by 9.80 m/s. Therefore, the rock will fall 49.8 m during the next 1.00 s.
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