University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 2 - Motion Along a Straight Line - Problems - Exercises: 2.22

Answer

(a) $a = 2440~m/s^2$ (b) $x = 1.10~m$

Work Step by Step

(a) $a = \frac{v-v_0}{t} = \frac{73.14~m/s}{0.0300~s}$ $a = 2440~m/s^2$ (b) $x = \frac{v^2-v_0^2}{2a} = \frac{(73.14~m/s)^2-0}{(2)(2440~m/s^2)}$ $x = 1.10~m$
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