Answer
(a) $a = 675 ~m/s^2$
(b) $t = 66.7~ms$
Work Step by Step
(a) $a = \frac{v^2-v_0^2}{2x} = \frac{(45.0 ~m/s)^2 - 0}{(2)(1.50 ~m)} = 675 ~m/s^2$
(b) $t = \frac{v-v_0}{a} = \frac{45.0~m/s}{675~m/s^2}$
$t = 0.0667~s = 66.7 ~ms$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 59: 2.21
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