University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 14 - Periodic Motion - Problems - Exercises - Page 462: 14.49

Answer

$g = 10.7~m/s^2$

Work Step by Step

We can find the period of the oscillations. $T = \frac{time}{cycles}$ $T = \frac{136~s}{100~swings}$ $T = 1.36~s$ We can find the value of $g$ on this planet. $T = 2\pi~\sqrt{\frac{L}{g}}$ $g = \frac{(2\pi)^2~L}{T^2}$ $g = \frac{(2\pi)^2(0.500~m)}{(1.36~s)^2}$ $g = 10.7~m/s^2$
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