University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 14 - Periodic Motion - Problems - Exercises - Page 462: 14.48

Answer

The period on Mars is 2.60 seconds.

Work Step by Step

(a) We can find the length of the pendulum. $T = 2\pi~\sqrt{\frac{L}{g}}$ $L = \frac{T^2~g}{(2\pi)^2}$ $L = \frac{(1.60~s)^2(9.80~m/s^2)}{(2\pi)^2}$ $L = 0.6355~m$ We can find the period on Mars. $T_M = 2\pi~\sqrt{\frac{L}{g_M}}$ $T_M = 2\pi~\sqrt{\frac{0.6355~m}{3.71~m/s^2}}$ $T_M = 2.60~s$ The period on Mars is 2.60 seconds.
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