University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 14 - Periodic Motion - Problems - Exercises - Page 462: 14.47


There will be 0.407 swings per second.

Work Step by Step

(a) We can find the period of the oscillation. $T = 2\pi~\sqrt{\frac{L}{g}}$ $T = 2\pi~\sqrt{\frac{1.50~m}{9.80~m/s^2}}$ $T = 2.46~s$ We can find the frequency of the oscillations. $f = \frac{1}{T}$ $f = \frac{1}{2.46~s}$ $f = 0.407~Hz$ The frequency is 0.407 Hz, which means that there will be 0.407 swings per second.
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