## University Physics with Modern Physics (14th Edition)

(a) We can find the period of the oscillation. $T = 2\pi~\sqrt{\frac{L}{g}}$ $T = 2\pi~\sqrt{\frac{1.50~m}{9.80~m/s^2}}$ $T = 2.46~s$ We can find the frequency of the oscillations. $f = \frac{1}{T}$ $f = \frac{1}{2.46~s}$ $f = 0.407~Hz$ The frequency is 0.407 Hz, which means that there will be 0.407 swings per second.