Answer
See explanation.
Work Step by Step
a. The frequency f $=\frac{1}{2 \pi}\sqrt{\frac{k}{m}}$. The mass is reduced, so the frequency increases.
b. The period T $=\frac{1}{f}$. The frequency increases so the period decreases.
c. The box’s amplitude is the same as before because it still reaches the same maximum distance from equilibrium.
d. The potential energy of the system is the same as before, $\frac{1}{2}kA^2$. This is also the maximum kinetic energy. The maximum KE is unaffected.
e. The maximum speed is the angular speed (which is higher, because $\omega =\sqrt{\frac{k}{m}}$) multiplied by the amplitude (which is unaffected). The maximum speed is larger.
