Answer
The angle between the two vectors is $124^{\circ}$
Work Step by Step
We know that the scalar product $\vec{A} \cdot \vec{B} = AB~cos(\phi)$, where $\phi$ is the angle between the two vectors.
We know that the vector product $\vec{A} \times \vec{B} = AB~sin(\phi)$, where $\phi$ is the angle between the two vectors.
$\frac{\vec{A} \times \vec{B}}{\vec{A} \cdot \vec{B}} = \frac{AB~sin(\phi)}{AB~cos(\phi)} = tan(\phi) = \frac{9.00}{-6.00} = -1.5$
$\phi = tan^{-1}(-1.5) = -56.3^{\circ}$
The angle between the two vectors is $180^{\circ}-56.3^{\circ}=124^{\circ}$
