Answer
(a) $A = (200~m)\hat{i}+(85~m)\hat{j} + (-30~m)\hat{k}$
(b) The distance walked along the path is 345 meters.
The magnitude of the displacement is 219 meters.
Work Step by Step
(a) Let $\hat{i}$ be east. Let $\hat{j}$ be north. Let $\hat{k}$ be up.
$A = (200~m)\hat{i}+(100~m-15~m)\hat{j} + (10\times-3.0~m)\hat{k}$
$A = (200~m)\hat{i}+(85~m)\hat{j} + (-30~m)\hat{k}$
(b) We can find the distance walked along the path.
$d = 30~m + 15~m+200~m+100~m = 345~m$
We can find the magnitude $R$ of the displacement.
$R = \sqrt{(200~m)^2+(85~m)^2+(-30~m)^2}$
$R = 219~m$
