#### Answer

We should run 28.8 m at an angle of $11.4^{\circ}$ north of east.

#### Work Step by Step

We can find the east component $d_x$ of the direction $d$.
$d_x = 38.0 - 18.0~sin(33.0^{\circ})$
$d_x = 28.2~m$
We can find the north component $d_y$ of the direction $d$.
$d_y = 20.8 - 18.0~cos(33^{\circ})$
$d_y = 5.70~m$
We can use $d_x$ and $d_y$ to find the magnitude of the distance $d$.
$d = \sqrt{(28.2~m)^2+(5.70~m)^2}$
$d = 28.8~m$
We can find the angle north of east.
$tan(\theta) = \frac{5.70}{28.2}$
$\theta = tan^{-1}(\frac{5.70}{28.2}) = 11.4^{\circ}$
We should run 28.8 m at an angle of $11.4^{\circ}$ north of east.