## University Physics with Modern Physics (14th Edition)

Since the angle between the ropes is $72.0$, each rope makes an angle of $36.0$ with the vertical axis. The vertical component $F_y$ of the force $F$ in each rope pulls up with a force of $\frac{372 ~N}{2}$ which is 186 N. $F_y = F ~cos(36.0^{\circ}) = 186 ~N$ $F = \frac{186 ~N}{cos(36.0^{\circ})} = 230 ~N$ Each rope pulls with a force of 230 N.