Answer
See explanation.
Work Step by Step
a. Assume the heart is roughly a cube that is S=0.1 m on a side.
The volume of the heart is $V=S^3$.
The mass of the heart, assuming that it is 98 percent water and the rest is air, is $M = 0.98V \times \frac{1000kg}{m^3}=1\times10^0 kg$.
b. Assume the cell is roughly a cube that is S=$0.5\times 10^{-6} m$ on a side.
The volume of the cell is $V=S^3$.
The mass of the cell, assuming that it is 98 percent water and the rest is air, is $M = 0.98V \times \frac{1000kg}{m^3}=1\times10^{-16} kg$.
c. Assume the bee is roughly a cube that is S=$1\times 10^{-2} m$ on a side.
The volume of the cell is $V=S^3$.
The mass of the bee, assuming that it is 98 percent water and the rest is air, is $M = 0.98V \times \frac{1000kg}{m^3}=1\times10^{-3} kg$.
