## University Physics with Modern Physics (14th Edition)

$2\times10^5$ drops.
Estimate the radius of a drop to be R=0.1 cm. Calculate the drop volume $V = \frac{4 \pi}{3}(R)^3$. The number of drops in 1.0 liter is $\frac{1000 cm^3}{V}=2\times10^5$ drops.