University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 28: 1.15


The percent error is 0.44998%

Work Step by Step

We can find the number of seconds in one year. Let's assume that one year has 365.24 days per year. $1 ~year = (365.24 ~days/year)(24 ~h/day)(3600 ~s/h)$ $1 ~year = 3.1557 \times 10^7~s$ A good approximation for the number of seconds per year is $\pi \times 10^7 ~s$. We can find the percent error in this approximation. The percent error is: $\frac{(3.1557 \times 10^7~s) - (3.1415 \times 10^7 ~s)}{(3.1557 \times 10^7~s)}\times 100\% = 0.44998\%$
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