University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 28: 1.12


a) $4.10\times10^{5}$ µg/day b) 0.900g c) 2 tablets each day d) 0.070 mg/day

Work Step by Step

1mg=$10^{-3}g$ 1µg=$10^{-6}g$ 1kg=$10^{3}g$ a) $(410mg/day)(\frac{10^{-3}g}{1mg})(\frac{1µg}{10^{-6}g})$= $4.10\times10^{5}$ µg/day b) (12mg/kg)(75kg)=$(900mg)(\frac{10^{-3}g}{1mg})$=0.900g c) mass of each tablet=m=(2.0mg)$(\frac{10^{-3}g}{1mg})$=$2.0\times10^{-3} g/tablet$ number of tablets required=$\frac{0.0030g/day}{2.0\times10^{-3} g/tablet}=1.5 tablet/day\approx2 tablet/day$ d) (0.000070 g/day)$(\frac{1mg}{10^{-3}g})$=0.070 mg/day
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