Answer
a) See answer below
b) $\Delta S=-33.36\ kJ/K$
c) $S_{gen}=4.44\ kJ/K$
Work Step by Step
From tables A-4 to A-6:
Initial ($x_1=1, T_1=100°C$): $v_1=1.6720\ m³/kg,\ u_1=2506.05\ kJ/kg,\ s_1=7.3542\ kJ/kg.K$
Final ($v_2=v_1, T_2=25°C$): $x_2=0.03856,\ u_2=193.67\ kJ/kg,\ s_2=0.6830\ kJ/kg.K$
a) On a T-v diagram the process starts at the saturation curve and occurs at constant v with a decrease in T.
b) $\Delta S=m(s_2-s_1),\ m=5\ kg$
$\Delta S=-33.36\ kJ/K$
c) $Q=\Delta U=m(u_2-u_1)$
$Q=-11,562\ kJ$ (out)
$S_{gen}=\Delta S - \frac Q{T_{surr}},\ T_{surr}=298\ K$
$S_{gen}=4.44\ kJ/K$
