Answer
$Q=219.9\ kJ$
$W=175.6\ kJ$
Work Step by Step
Initial ($x_1=1, T_1=200°C$): $u_1=2594.2\ kJ/kg,\ s_1=6.4302\ kJ/kg.K$
Final ($P_2=800\ kPa, T_2=T_1$): $u_2=2631.1\ kJ/kg,\ s_2=6.8177\ kJ/kg.K$
$\Delta S=\frac{Q}{T}$
$Q=Tm(s_2-s_1)$
$T=473\ K,\ m=1.2\ kg$
$Q=219.9\ kJ$
$Q-W=\Delta U$
$W=m(u_1-u_2)+Q$
$W=175.6\ kJ$
