Answer
A
Work Step by Step
$\eta=1-\frac{T}{T_H}=\eta=1-\frac{T_L}{T}$
$T^2=T_HT_L$
$T_H=1300\ K,\ T_L=300\ K$
$T=624.5\ K$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 327: 6-168
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