Answer
A
Work Step by Step
$Q_H=mc_v\Delta T,\ m=1200\ kg,\ c_v=0.718\ kJ/kg.°C,\ \Delta T=(22-7)°C$
$Q_H=12,924\ kJ$
$COP_{HP}=Q_H/W_i=3.2$
$W_i=4039\ kJ$
$\dot{W}_i=5\ kW$
$\dot{W}_i=W_i/\Delta t$
$\Delta t=13.46\ min$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 327: 6-164
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