Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 327: 6-166

Answer

E

Work Step by Step

$COP_R=\dfrac{1}{\frac{T_H}{T_L}-1}$ $T_H=35°C,\ T_L=20°C$ $COP=19.53$ $COP_R=\dot{Q}_L/\dot{W}_i,\ \dot{Q}_L=32\ kJ/s$ $\dot{W}_i=1.638\ kW$
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