Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 321: 6-117

Answer

$C=\$4.06/year$

Work Step by Step

$m=5\ kg/pan\times 3\ pans/week \times 52\ weeks/year=780\ kg/year$ $Q=mc\Delta T$ $c=3.90\ kJ/kg.°C,\ \Delta T=(95-23)°C=72°C$ $Q=219.02\ MJ/year$ $E=Q/COP,\ COP=1.5$ $E=40.56\ kWh/year$ $C=E\times p,\ p=\$0.10/kWh$ $C=\$4.06/year$
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