Answer
$f=38.8\%$
Work Step by Step
$W_e=\frac{\$170/year}{\$0.0125/kWh}$
$W_e=1360\ kWh/year$
$\dot{W}_e=W_e/\Delta t=0.4\ kW$
$\Delta t=3400\ h/year$
$f=0.388=38.8\%$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 321: 6-115
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