Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 319: 6-98E

Answer

$\dot{W}_i=0.879\ kW$

Work Step by Step

$COP_R=\dfrac{1}{1-\frac{T_L}{T_H}}$ Given $T_H=540°R,\ T_L=450°R$ $COP_R=5$ $COP_R=\dot{Q}_L/\dot{W}_i$ With $\dot{Q}_L=15000\ Btu/h$ $\dot{W}_i=0.879\ kW$
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