Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 319: 6-102

Answer

a) $T_L=10°C$: $COP_{HP}=29.3$ b) $T_L=-5°C$: $COP_{HP}=11.7$ c) $T_L=-30°C$: $COP_{HP}=5.86$

Work Step by Step

$COP_{HP}=\dfrac{1}{1-\frac{T_L}{T_H}}$ Given $T_H=35°C$ a) $T_L=10°C$: $COP_{HP}=29.3$ b) $T_L=-5°C$: $COP_{HP}=11.7$ c) $T_L=-30°C$: $COP_{HP}=5.86$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.