Answer
It is powerful enough.
Work Step by Step
$COP_{HP}=\dfrac{1}{1-\frac{T_L}{T_H}}$
Given $T_H=25°C,\ T_L=4°C$
$COP_{HP}=14.19$
$COP_{HP}=\dot{Q}_H/\dot{W}_i$
With $\dot{Q}_H=110000\ kJ/h$
$\dot{W}_i=2.15\ kW$
Since $\dot{W}_{required} \lt \dot{W}_{actual}$, it is powerful enough.