## Thermodynamics: An Engineering Approach 8th Edition

$COP_{HP}=\dfrac{1}{1-\frac{T_L}{T_H}}$ Given $T_H=25°C,\ T_L=4°C$ $COP_{HP}=14.19$ $COP_{HP}=\dot{Q}_H/\dot{W}_i$ With $\dot{Q}_H=110000\ kJ/h$ $\dot{W}_i=2.15\ kW$ Since $\dot{W}_{required} \lt \dot{W}_{actual}$, it is powerful enough.