Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 273: 5-203

Answer

A

Work Step by Step

$\dot{W}_s=\dot{m}(h_1-h_2)$ $\dot{m}=1.25\ kg/s,\ h_2=297.00\ kJ/kg,\ h_1=332.74\ kJ/kg$ $\dot{W}_s=44.68\ kW$
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