Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 273: 5-201

Answer

A

Work Step by Step

$\dot{W}_s=\dot{m}(h_2-h_1)$ $\dot{m}=1.30\ kg/s,\ h_2=3162.2\ kJ/kg,\ h_1=2769.1\ kJ/kg$ $\dot{W}_s=511.03\ kW$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.