Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 273: 5-199

Answer

C

Work Step by Step

$\dot{W}_s+\dot{Q}=\dot{m}c_p(T_1-T_2)$ $\dot{Q}=15\ kJ/s,\ \dot{m}=0.1\ kg/s,\ c_p=1.005\ kJ/kg.K,\ T_1=1500\ K,\ T_2=900\ K$: $\dot{W}_s=45.3\ kW$
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