Answer
$\dot{Q}=0.3\ kW$
Work Step by Step
From table A-11:
Inlet ($T_1=10°C,\ x_1=1$): $h_1=256.22\ kJ/kg$
Outlet ($P_2=1.4\ MPa,\ h_2=281.39\ kJ/kg$)
$\dot{W}_s+\dot{m}(h_1+\mathcal{V}_1^2/2)=\dot{Q}+\dot{m}(h_2+\mathcal{V}_2^2/2)$
$\dot{Q}=\dot{W}_s+\dot{m}(h_1-h_2+\dfrac{\mathcal{V}_1^2-\mathcal{V}_2^2}2)$
$\dot{W}_s=132.4\ kW,\ \dot{m}=5\ kg/s,\ \mathcal{V}_1\approx0,\ \mathcal{V}_2=50\ m/s$
$\dot{Q}=0.3\ kW$
