Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 269: 5-171

$\dot{W}_s=152\ kW$

$\dot{m}=\frac{P_1A_1\mathcal{V}_1}{RT_1}$ $P_1=110\ kPa,\ R=2.0769\ kJ/kg.K,\ T_1=20°C,\ A_1=0.1\ m²,\ \mathcal{V}_1=9\ m/s$ $\dot{m}=0.1627\ kg/s$ $\dot{W}_s+\dot{m}h_1=\dot{m}h_2$ $\dot{W}_s=\dot{m}c_p(T_2-T_1)$ $c_p=5.1926\ kJ/kg.K,\ T_2=200\ K,\ T_1=20\ K$ $\dot{W}_s=152\ kW$