Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 268: 5-164

Answer

$C=\$22.9/month$

Work Step by Step

$\dot{m}=\frac{P\dot{V}}{RT}$ $P=101.3\ kPa,\ R=0.287\ kJ/kg.K,\ T=22°C,\ \dot{V}=0.030\ m³/s$ $\dot{m}=0.03590\ kg/s$ $\dot{Q}+\dot{m}h_1=\dot{m}h_2$ $\dot{Q}=\dot{m}c_p(T_2-T_1)$ $c_p=1.005\ kJ/kg.K,\ T_2=22°C,\ T_1=12.2°C$ $\dot{Q}=0.3536\ kW$ $C=p\dot{Q}\Delta t$ $p=\$0.12/kWh,\ \Delta t=720\ h=1 month$ $C=\$22.9/month$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.