Answer
$\dfrac{\dot{Q}_{LA}}{\dot{Q}_D}=1.22$
Work Step by Step
$\dot{Q}+\dot{m}h_1=\dot{m}h_2$
$\dot{Q}=\dot{m}c_p(T_2-T_1)$
$\dot{m}=\frac{P}{RT}\dot{V}$
$\dot{m}=\frac{P}{RT}ACH.V$
$\dot{Q}=\frac{P}{RT}ACH.V.c_p(T_2-T_1)$
$\dfrac{\dot{Q}_{LA}}{\dot{Q}_D}=\dfrac{[\frac{P}{RT}ACH.V.c_p(T_2-T_1)]_{LA}}{[\frac{P}{RT}ACH.V.c_p(T_2-T_1)]_D}$
$\dfrac{\dot{Q}_{LA}}{\dot{Q}_D}=\dfrac{P_{LA}}{P_D}$
$P_{LA}=101\ kPa,\ P_D=83\ kPa$
$\dfrac{\dot{Q}_{LA}}{\dot{Q}_D}=1.22$
