Answer
$\dot{W}_{flow}=1.72\ kW$
$\dot{W}_{pressure}=4.48\ kW$
Work Step by Step
For ideal gases:
$\dot{m}=\frac{P\dot{V}}{RT}$
Given $P_1=120\ kPa,\ R=0.287\ kJ/kg.K,\ T_1=293\ K,\ \dot{V}_1=0.015\ m³/s$
$\dot{m}_1=\dot{m}_2=0.02140\ kg/s$
$w_{flow}=P_2v_2-P_1v_1=RT_2-RT_1$
Since $T_2=300°C$: $w_{flow}=80.36\ kJ/kg$
$\dot{W}_{flow}=w_{flow}\dot{m}$
$\dot{W}_{flow}=1.72\ kW$
$\dot{W}_{total}=\dot{W}_{pressure}+\dot{W}_{flow}=6.2\ kW$
$\dot{W}_{pressure}=4.48\ kW$
