Answer
$\rho_2=2.64\ kg/m³$
Work Step by Step
$\dot{m}_1=\dot{m}_2$
$\rho_1 A_1\mathcal{V}_1=\rho_2 A_2\mathcal{V}_2$
Given $\rho_1=4.18\ kg/m³,\ A_1/A_2=2,\ \mathcal{V}_1=120\ m/s,\ \mathcal{V}_2=380\ m/s$:
$\rho_2=2.64\ kg/m³$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 265: 5-137
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