Answer
$\dot{m}=6.55\ kg/s$
Work Step by Step
$\dot{m}=\rho A_c\mathcal{V}$
Given $\rho=7854\ kg/m³,\ A_c=1\times0.005=0.005\ m²,\ \mathcal{V}=10\ m/min$:
$\dot{m}=6.55\ kg/s$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 265: 5-136
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