Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 261: 5-111

Answer

$T_l=389.5°C$ $w_{flow}=288\ kJ/kg$

Work Step by Step

For discharges $h_{line}=u_{tank}$ From table A-6: Tank ($P_t=4\ MPa, T_t=550°C$): $u_t=3189.5\ kJ/kg$ Line ($P_l=4\ MPa, h_l=u_t$): $T_l=389.5°C,\ u_l=2901.5\ kJ/kg$ $w_{flow}=h_l-u_l$ $w_{flow}=288\ kJ/kg$
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