Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 261: 5-102E

Answer

$L=4500\ ft$

Work Step by Step

From the energy balance: $\dot{Q}+\dot{m}h_1=\dot{m}h_2$ $\dot{Q}=\dot{m}c_p(T_2-T_1)$ and since $\dot{m}=4\ lbm/s,\ c_p=1.0\ Btu/lbm.°F,\ T_2=180°F,\ T_1=55°F$: $\dot{Q}=500\ Btu/s=1.8\times10^6\ Btu/h$ $\dot{Q}=\grave{Q}.L,\ \grave{Q}=400\ Btu/h.ft$ $L=4500\ ft$
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