Answer
$\dot{m}=0.0304\ kg/s$
Work Step by Step
From the energy balance:
$\dot{W}_e+\dot{m}h_1=\dot{m}h_2$
$\dot{W}_e=\dot{m}c(T_2-T_1)$
Given $\dot{W}_e=7\ kW,\ c=4.184\ kJ/kg.°C,\ T_2=75°C,\ T_1=20°C$:
$\dot{m}=0.0304\ kg/s$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 261: 5-107
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