Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 256: 5-57

Answer

$\dot{m}=0.674\ kg/s$

Work Step by Step

From table A-17: Inlet ($T_1=25°C$): $h_1=298.2\ kJ/kg$ Outlet ($T_2=347°C$): $h_2=628.7\ kJ/kg$ From the energy balance: $\dot{m}(h_1+\mathcal{V}_1^2/2)+\dot{W}_s=\dot{m}(h_2+\mathcal{V}_2^2/2)+\dot{Q}$ Given $\mathcal{V}_1\approx0,\ \mathcal{V}_2=90\ m/s,\ \dot{W}_s=250\ kW,\ \dot{Q}=1500\ kJ/min$: $\dot{m}=0.674\ kg/s$
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