Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 256: 5-50

$\dot{W}_s=872\ kW$

From the energy balance: $\dot{W}_s+\dot{m}h_1=\dot{m}h_2+\dot{Q}$ With $h_2=h_1+c_p(T_2-T_1)$ $\dot{W}_s=\dot{m}(c_p(T_2-T_1)+\dot{q})$ Given $\dot{m}=60\ kg/min,\ c_p=5.1926\ kJ/kg,\ T_2=460K,\ T_1=295\ K,\ \dot{q}=15\ kJ/kg$: $\dot{W}_s=872\ kW$