Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 253: 5-16

Answer

$m_2=411.5\ kg$

Work Step by Step

The material balance for the tank: $\Delta m = (\dot{m}_{in}-\dot{m}_{out})\Delta t$ Constant density: $\Delta V = (\dot{V}_{in}-\dot{V}_{out})\Delta t$ With $V_1=0.3\ m³,\ \dot{V}_{in}=15L/min=0.00025m³/s$, $\dot{V}_{out}=\frac{\pi}{4}D^2\nu_{out},\ D=0.02m, \nu_{out}=0.5\ m/s, \Delta t=20 min$: $V_2=0.4115\ m³$ With $\rho=1000\ kg/m³$: $m_2=411.5\ kg$
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