Answer
$\dot{m}=0.238\ kg/min$
Work Step by Step
$\dot{m}=\rho\dot{V}=0.7kg/m³\times0.34m³/min=0.238\ kg/min$
$\dot{V}=\frac{\pi}{4}D_{min}^2\nu_{max}$
With $\nu_{max}=110\ m/min$:
$D_{min}=0.063\ m$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 253: 5-12
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