Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 208: 4-133

Answer

$T_2=85.7°C$

Work Step by Step

For ideal gases: $PV=mRT$ Given $P_1=500kPa,\ V_1=1m³,\ T_{1,He}=40°C,\ T_{1,N_2}=120°C$, $R_{N_2}=0.2968\ kJ/kg.K, R_{He}=2.0769\ kJ/kg.K$ solving for the masses we get: $m_{N_2}=4.287\ kg,\ m_{He}=0.7691\ kg$ The energy balance for the system is: $\Delta U_{N_2}+\Delta U_{He}=0$ With $c_{v,N_2}=0.743\ kJ/kg.K,\ c_{v,He}=3.1156\ kJ/kg.K$: solving for the final temperature: $T_2=85.7°C$
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