Answer
$T_2 = 394.45 K$
$W = 2.95 kJ$
Work Step by Step
From the ideal gas table: $n = 1.4$
Deriving from the polytropic equation and the equation of state for ideal gases we have:
$\frac{P^{(n-1)}}{T^n} = constant \rightarrow T_2^n = T_1^n (\frac{P_2}{P_1})^{n-1}$
With:
$P_2 = 80\ kPa, P_1 = 130\ kPa, T_1 = 180°C + 273.15 = 453.15\ K, V_1=0.07\ m³$
$T_2 = 394.45 K$
For the final volume:
$V_2^n=\frac{P_1}{P_2}V_1^n$
$V_2 = 0.099\ m³$
The work for a polytropic process is:
$W = \frac{P_2V_2-P_1V_1}{1-n}$
$W = 2.95 kJ$
