Answer
$W = 50.22 kJ$
Work Step by Step
$W = P_0V_0\ln(\frac{V_f}{V_0}) = P_0V_0\ln(\frac{P_0}{P_f})$
With
$P_0 = 150 kPa, V_0 = 0.2 m³, P_f = 800kPa$
$W = -50.22 kJ$
Since the work is done on the system: $W = 50.22 kJ$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 196: 4-2
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