Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 196: 4-4

Answer

$W = -5.14\ BTU$

Work Step by Step

Since we're given the P-V diagram, the work is the are under the curve: $W_{1-2} = (V_2 - V_1)\frac{P_2+P_1}{2}$ $W_{2-3} = (V_3 - V_2)P_3$ With $V_1 =1 ft³, V_2 = 3.3 ft³, V_3 = 2 ft³, P_1 = 15\ psia, P_2=P_3 = 300\ psia$ $c_1 = 144 \frac{psf}{psi}, c_2 = \frac{1\ BTU}{778.2\ lbf.ft}$ $W_{1-2} = (2.3 ft³)157.5psi \times c_1c_2 = 67.03 BTU$ $W_{2-3} = (-1.3ft³)300 psia \times c_1c_2 = -72.16 BTU $ $W = W_{1-2} +W_{2-3} $ $W = -5.14\ BTU$
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