Answer
See the image
Work Step by Step
a) From table A-11
$v=0.0007644\frac{m^3}{kg}$
As $T\lt T_{sat}$ is a compressed liquid
b) From table A-11
$P=414.89kPa$
As $0.0007929\frac{m^3}{kg}\lt v\lt 0.049466\frac{m^3}{kg}$ is a saturated mixture.
c) From table A-12
$T=33.45^{\circ}C$
$v=0.024091\frac{m^3}{kg}$
d) From table A-13
$v=0.046318\frac{m^3}{kg}$
As $T\gt T_{sat}$ is a superheated vapor
