Answer
See the image
Work Step by Step
a) From table A-4
$P=361.53kPa$
As $0.001080\frac{m^3}{kg}\lt v\lt 0.50850\frac{m^3}{kg}$ is a saturated mixture.
b) From table A-5
$T=155.46^{\circ}C$
$v=0.001097\frac{m^3}{kg}$
c) From table A-4
$v=0.001065\frac{m^3}{kg}$
As $T\lt T_{sat}$ is a compressed liquid
d) From table A-6
$P=2500kPa$
As $T$ is to high is a superheated vapor
