Answer
See the picture
Work Step by Step
a) From table A-5
$T=143.61^{\circ}C$
As $604.22\frac{kJ}{kg}\lt u\lt 2553.1\frac{kJ}{kg}$ is a saturated mixture.
b) From table A-4
$P=2319.6kPa$
$u=2601.3\frac{kJ}{kg}$
c) From table A-4
$u=806.00\frac{kJ}{kg}$
As $T\lt T_{sat}$ is a compressed liquid
d) From table A-6
Interpolating $T=466.24^{\circ}C$
As $u\gt u_{g}$ is a superheated vapor
